n(n-1)! = n[(n-1)(n-2)(n-3)...(3)(2)(1)] = n(n-1)(n-2)(n-3)...(3)(2)(1) = ?
Can someone tell me how I can approach this problem because im not sure if its a formula based question, the answer is suppose to be 5/17.
A bag contains 10 red jellybeans and 8 black jellybeans.
What is the probability that 2 jellybeans selected at random are red?