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  1. #1
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    story problem

    STORY PROBLEM-
    AT THE COOKIE COUNTER THERE WERE 6 MORE CHOCOLATE MINT COOKIES THAN WHITE FROSTED COOKIES, BUT THE SUM OF THE MINT AND FROSTED WAS EQUAL TO THE TOTAL OF PEANUT BUTTER COOKIES. THEY SAW EXACTLY TWICE AS MANY PEANUT BUTTER COOKIES AS OATMEAL COOKIES. THERE WERE ON THIRD AS MANY PEANUT BUTTER AS CHOCOLATE CHIP.THERE WERE 36 CHOCOLATE CHIP COOKIES.

    HOW MANY CHOCOLATE CHIP_____
    HOW MANY CHOCATATE MINT______
    OATMEAL_______
    PEANUT BUTTER_________
    WHITE FROSTED__________
    TOTAL ___________________
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  2. #2
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    Quote Originally Posted by mhughes21 View Post
    STORY PROBLEM-
    AT THE COOKIE COUNTER THERE WERE 6 MORE CHOCOLATE MINT COOKIES THAN WHITE FROSTED COOKIES, BUT THE SUM OF THE MINT AND FROSTED WAS EQUAL TO THE TOTAL OF PEANUT BUTTER COOKIES. THEY SAW EXACTLY TWICE AS MANY PEANUT BUTTER COOKIES AS OATMEAL COOKIES. THERE WERE ON THIRD AS MANY PEANUT BUTTER AS CHOCOLATE CHIP.THERE WERE 36 CHOCOLATE CHIP COOKIES.

    HOW MANY CHOCOLATE CHIP_____
    HOW MANY CHOCATATE MINT______
    OATMEAL_______
    PEANUT BUTTER_________
    WHITE FROSTED__________
    TOTAL ___________________
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    You can figure out what the symbols mean:

    x = y + 6

    x + y = z

    z = 2w

    z = 12


    Solve for x, y and w.
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  3. #3
    MHF Contributor
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    AT THE COOKIE COUNTER THERE WERE 6 MORE CHOCOLATE MINT COOKIES THAN WHITE FROSTED COOKIES,
    M = F +6 -------------(1)

    BUT THE SUM OF THE MINT AND FROSTED WAS EQUAL TO THE TOTAL OF PEANUT BUTTER COOKIES.
    M +F = P --------------------(2)

    THEY SAW EXACTLY TWICE AS MANY PEANUT BUTTER COOKIES AS OATMEAL COOKIES.
    P = 2(Ot) -----------------(3)

    THERE WERE ON THIRD AS MANY PEANUT BUTTER AS CHOCOLATE CHIP.
    P = (1/3)C -------------------(4)

    THERE WERE 36 CHOCOLATE CHIP COOKIES.
    C = 36 --------------------(5)

    So, combining Eq.(5) and Eq.(4),
    P = (1/3)(36) = 12 peanut butter cookies

    Substitute that into Eq.(3),
    12 = 2(Ot)
    Ot = 12/2 = 6 oatmeal cookies.

    Substitute the P = 12 into Eq.(2),
    M +F = 12
    M = 12 -F -------(6)

    M from Eq.(1) = M from Eq.(6),
    F +6 = 12 -F
    F +F = 12 -6
    2F = 6
    F = 6/2 = 3 white frosted cookies

    Hence, M = F +6 = 3 +6 = 9 choc mint cookies
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