i need to solve this equation for x using base 10 logarithms... 13^(x-3) = 18^(3x)
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Originally Posted by Manizzle i need to solve this equation for x using base 10 logarithms... 13^(x-3) = 18^(3x) so take the log of both sides now recall the rule: now proceed
yes i know that rule but i don't know how then to solve for x
Originally Posted by Manizzle yes i know that rule but i don't know how then to solve for x ok, so that means you got to the point now what is the problem? and are constants. how would you solve something like ? just treat the logs like constants. they are just numbers. solve for as you would in any regular algebraic equation
Originally Posted by Manizzle i need to solve this equation for x using base 10 logarithms... 13^(x-3) = 18^(3x) Sorry, Jhevon. But I had already done the grunt work on this so here's the rest of it.
Originally Posted by masters Sorry, Jhevon. But I had already done the grunt work on this so here's the rest of it. that's fine, Masters. I would have preferred if you left it as log(13) and log(18) though as opposed to finding the decimal approximations.
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