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Math Help - word problem, consecutive integers.

  1. #1
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    Question word problem, consecutive integers.

    The perimeter of a triangle is 78'. The lengths of the sides are represented by 3 conscutive integers. What are those lengths. I have no idea where to start with this one??????????

    Thanks in advance!
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  2. #2
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    The lengths of the sides are represented by 3 conscutive integers. Therefore, the sum of the lengths of the sides (Perimeter) is:

    P = n + (n+1) + (n+2)

    P is given, so solve for n.
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  3. #3
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    Hint: let the length of this triangle be n,n+1,n+2 (you may these choose this concecutive number to be m-1,m,m+1 as well). The second choice give you a nicer computation.
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  4. #4
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    Still a bit confused on this one, I came up with an answer of

    P= 78 consecutive numbers are 25,26,27 but I am not sure how to put this as an equation.
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  5. #5
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    Quote Originally Posted by tpoma View Post
    Still a bit confused on this one, I came up with an answer of

    P= 78 consecutive numbers are 25,26,27 but I am not sure how to put this as an equation.
    Chop Suey gave you the equation.

    P = n + (n+1) + (n+2)


    78 = n + (n+1) + (n+2)
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  6. #6
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    I guess what I am asking is my final answer is going to look like this.....


    78= 25+(26+1)+(27+2) That just does not look right.
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  7. #7
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    Quote Originally Posted by tpoma View Post
    I guess what I am asking is my final answer is going to look like this.....


    78= 25+(26+1)+(27+2) That just does not look right.
    You're right, it doesn't. You should have put 25 in place of n in every instance instead of the 26 and 27 that you did put in.

    78=25+(25+1)+(25+2)
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  8. #8
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    That makes sense now...I see what I did. Thanks for all your help!!
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