Need help simplifying this equation completely: 2*ln(e^A) + 3*lnB^e Thanks!
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Originally Posted by TheTwoJ Need help simplifying this equation completely: 2*ln(e^A) + 3*lnB^e Thanks! $\displaystyle \ln (e^A) = A \ln e = A \cdot 1 = A$ And $\displaystyle \ln B^e = e \ln B$ Now you can use those two to simplify this equation.
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