y cubed minus x cubed. Many thanks!
Follow Math Help Forum on Facebook and Google+
Recall that difference of cubes can be factored like the following: $\displaystyle a^3 - b^3 = (a-b)(a^2+ab+b^2)$ The sum of cubes is also factored in a similar way: $\displaystyle a^3 + b^3 = (a+b)(a^2-ab+b^2)$
Originally Posted by Chop Suey Recall that difference of cubes can be factored like the following: $\displaystyle a^3 - b^3 = (a-b)(a^2+ab+b^2)$ The sum of cubes is also factored in a similar way: $\displaystyle a^3 + b^3 = (a+b)(a^2-ab+b^2)$ So simple yet so brilliant! Thank you v. much! How do I thank you properly? Is it by giving rep?
Originally Posted by bluebiro So simple yet so brilliant! Thank you v. much! How do I thank you properly? Is it by giving rep? Yes....give him a rep!
View Tag Cloud