Help would be greatly appreciated...
-2-²
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-2²
(Dotted line is a fraction line) I understand that 1/-2-² = -2²... but I am not sure how to do this one using that formula.
Hello, violinist!
$\displaystyle \frac{-2^{-2}}{-2^2} $
Important . It does not say $\displaystyle (-2)^{-2}$ or $\displaystyle (-2)^2$
. . . . . . . . . .Only the $\displaystyle 2$ is raised to a power.
We have: .$\displaystyle \frac{-(2^{-2})}{-(2^2)} \;=\;\frac{2^{-2}}{2^2}$ . . . (Negative $\displaystyle \div$ negative = positive)
Then: .$\displaystyle \frac{2^{-2}}{2^2} \;=\;2^{-2-2} \;=\;2^{-4}$ . . . (Division rule for exponents)
Finally: .$\displaystyle 2^{-4} \;= \;\frac{1}{2^4} \;=\;\frac{1}{16}$