Just a little hint for this one please. $\displaystyle \frac {1}{1+ \sqrt{2}+ \sqrt{3}}$ Thank you.
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Originally Posted by Ting Just a little hint for this one please. $\displaystyle \frac {1}{1+ \sqrt{2}+ \sqrt{3}}$ Thank you. First, multiply both numerator and denominator by (1 +sqrt(2)) -sqrt(3) to rationalize the sqrt(3) Or, by (1 +sqrt(3)) -sqrt(2) to rationalize the sqrt(2)
Thank you very much. I should have thought of trying that myself. Got $\displaystyle \frac {1+\sqrt{2}-\sqrt{3}}{2 \sqrt{2}}$ and then: $\displaystyle \frac {\sqrt{2}}{4}-\frac {\sqrt{6}}{4}+\frac {1}{2}$ Thanks again.
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