Solve, using matrices, the pair of simultaneous linear eqns,
3x= 2y + 8
14= 5x -4y
yea but my answer is so big x=30,y=41 and my solution just works for the first eqn.
the paper's answer is x=2 y=-1
i dunno where went wrong but from these 2 simultaneous qns :
3x-2y=8 -(1)
5x-4y=14
im wondering do u nid to do something to them[like (1)x2?] or u can just straight-away write out the matrix from there??
$\displaystyle \begin{bmatrix}3 & -2\\5& -4\end{bmatrix} \, \begin{bmatrix}x \\ y \end{bmatrix} = \begin{bmatrix}8 \\ 14 \end{bmatrix}$
which has the form AX = B. Left multiply both sides by the inverse of matrix A to solve for X. The solution to the equations is the matrix elements of X.