I dont get this. What will the tens and the units digits of 2008^2008 be?
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i think the unit digit is 8, but i dont know the tenths digit.
Tens digit = 1 Unit digit = 6 the last 2 digits of $\displaystyle 2008^{2008}$ is 16.
"clarebear14tens and units digits I dont get this. What will the tens and the units digits of 2008^2008 be? " Thought it was 44. Don't have time to check. sorry agree 16
Last edited by jaydee323; Oct 7th 2008 at 03:19 AM. Reason: correction
sorry i mistakely written as 8, the value of unit digit is 6.. but the tenths digit i dont know how to find. please explain that....
Tn = 2008^n A pattern which is 8 terms long emerges for last two digits T3 = T11 T4 = T12 T8 = T16 = . ... ...T2008 = 16
thanks for your reply and explanation but we can only substitute and find the results, or any relations or equations are there??
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