I suspect I'm just drawing a blank here, but I thought any number is divisible by 3 if the sum of its digits is divisible by 3.
Am I wrong about this? I came across the number 6111. The sum of its digits is 9. But when I divide 6111 by 3, I get .
I suspect I'm just drawing a blank here, but I thought any number is divisible by 3 if the sum of its digits is divisible by 3.
Am I wrong about this? I came across the number 6111. The sum of its digits is 9. But when I divide 6111 by 3, I get .
Good question. I was actually part-way through simplifying a fraction when I came across 6111. While subtracting/carrying in the division problem, I suavely made the 1 into a 10 instead of 11, henceOriginally Posted by topsquark
So yeah, it was really a problem w/division
I'm avoiding my calculator at all costs right now. Of course, it seems I'm regressing lately. Moving on to 2037, the sum of its digits is 12. I just tried dividing that by 2, and then tried again, and both times I got
Shouldn't 2 be going evenly into 2037?
I was browsing through my subscribed threads for problems that were never completely dealt with. This is one such thread that I'd like to understand. In response to Random's answer (or anyone else reading this), both my book and my previous instructor encouraged the use of calculators for checking answers, but discouraged their use for solving problems. I agree with the idea of not allowing the calculator to do any of my work for me (at this point in time).
By "the pair," I suppose you're referring to
And not
Since 4,753 is a prime number.
Given the restraint of solving by hand, I'm having difficulty determining how I might ascertain the pair's Highest Common Factor... especially if this is the only method available for simplifying this fraction in particular.