I seem to have a problem figuring out how to write this out.
"The sum of two numbers is 3 and twice the larger number is 36 more than three times the smaller number. Find the numbers."
Any help?
We can set up two equations:
$\displaystyle x+y=3$ ----- [sum of two different numbers, where x is the smaller, and y is the larger]
$\displaystyle 2y=36+3x$ -----[twice the larger number = 36 + three times the smaller number]
Can you solve this system of equations?
$\displaystyle \left\{\begin{array}{rcrcr}x&+&y&=&3\\-3x&+&2y&=&36\end{array}\right.$
--Chris