Let x be the liters of 60% antifreeze coolant and y be liters of pure water.
Then: x + y = 3.6
.6x + 0y = .5(3.6)
Solve the system for x and y, and of course your answer will be y.
No matter what I try, I just cannot figure this one out. Like I mentioned on the other thread, I'm not having any trouble solving them, just modeling them.
The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that, for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
Thank you so much!
I got the solution .6L. The only thing I don't quite understand is the set up. I mean, of course I know it's right. I was just wondering why you put everything where you did? I understand the x+y=3.6 just fine, it's the 0y I don't exactly understand. Because aren't you adding water? I don't know why I can't get this modeling down.. once I see it done it looks so easy.