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Math Help - inequalities problem

  1. #1
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    inequalities problem

    Please help due tomorrow

    -3b<1/5



    8a-8>7A-20


    3-{3/2x-3}> 1/2(x+5)
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by ms.butterfly View Post
    Please help due tomorrow

    -3b<1/5



    8a-8>7A-20


    3-{3/2x-3}> 1/2(x+5)
    -3b<\frac{1}{5}

    Multiply by 5 and then divide by -15. Don't forget to reverse the inequality.

    -15b<1

    b>-\frac{1}{15}

    Don't know what you want to do with the second one. It has two variables.

    Is this the third one?

    3-\left(\frac{3}{2}x-3\right)>\frac{1}{2}(x+5)
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  3. #3
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    yes, the second it I need addition and multiplication principles and yes that is the third one. I didn't know how to put it on the thread.
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  4. #4
    A riddle wrapped in an enigma
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    3-\left(\frac{3}{2}x-3\right)>\frac{1}{2}(x+5)

    First, remove parenthesis:

    3-\frac{3}{2}x+3>\frac{1}{2}x+\frac{5}{2}

    Multiply every term by 2 to eliminate the fractions:

    6-3x+6>x+5

    Combine terms:

    12-3x>x+5

    Subtract x from both sides, and subtract 12 to both sides:

    -4x>-7

    Divide by -4 (Remember to reverse the inequality sign because you are dividing by a negative number)

    x<\frac{7}{4}

    Still not sure what you want in your second one.
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