Please help due tomorrow
-3b<1/5
8a-8>7A-20
3-{3/2x-3}> 1/2(x+5)
$\displaystyle -3b<\frac{1}{5}$
Multiply by 5 and then divide by -15. Don't forget to reverse the inequality.
$\displaystyle -15b<1$
$\displaystyle b>-\frac{1}{15}$
Don't know what you want to do with the second one. It has two variables.
Is this the third one?
$\displaystyle 3-\left(\frac{3}{2}x-3\right)>\frac{1}{2}(x+5)$
$\displaystyle 3-\left(\frac{3}{2}x-3\right)>\frac{1}{2}(x+5)$
First, remove parenthesis:
$\displaystyle 3-\frac{3}{2}x+3>\frac{1}{2}x+\frac{5}{2}$
Multiply every term by 2 to eliminate the fractions:
$\displaystyle 6-3x+6>x+5$
Combine terms:
$\displaystyle 12-3x>x+5$
Subtract x from both sides, and subtract 12 to both sides:
$\displaystyle -4x>-7$
Divide by -4 (Remember to reverse the inequality sign because you are dividing by a negative number)
$\displaystyle x<\frac{7}{4}$
Still not sure what you want in your second one.