Problem:
(2^9/2^8 * sixth root of 3)^4
We have to solve it labeling each step.
I have it down to
(2^1 * sixth root of 3)^4 by the quotient of powers
I am stuck from there, though.
(2^9/2^8 * sixth root of 3)^4
You are getting closer.
2^9/2^8 = 2^1 or more commonly known as 2.
because 2^(9-8) = 2^1
sixth root of three can be written as 3^(1/6)
so.
[ 2*3^(1/6) ]^4
Apply the 4 to inside the bracket
2^4 * 3^[ (1/6)*4) ]
16 * 3^(4/6)
16 * 3^(2/3)
=33.281341