Use factoring to solve the equation for real values of the variables
z^3/2 - 2^1/2 = 0
I think i'm making it harder then it realy is please help
Hi again civiliam,
We have $\displaystyle z^{\frac{3}{2}}-2^{\frac{1}{2}}=0$ . Now this leads to $\displaystyle z^{\frac{3}{2}}=2^{\frac{1}{2}}$ . Notice that to get $\displaystyle z$ we need to raise $\displaystyle z^{\frac{3}{2}}$ to the power of $\displaystyle \frac{2}{3}$ since we know that $\displaystyle (a^b)^c=a^{bc}$ . Hence raising both sides of the equation to the power $\displaystyle \frac{2}{3}$ yields $\displaystyle z=2^{\left(\frac{1}{2}\right)\left(\frac{2}{3}\rig ht)}=2^{\frac{1}{3}} $ .
Hope this helps.