Results 1 to 3 of 3

Math Help - HW Question Factoring

  1. #1
    Junior Member
    Joined
    Oct 2008
    Posts
    26

    HW Question Factoring

    I don't know how to go on about solving this...

    IT asks Use factoring to solve the equation for the real values of the variable

    y^4 - 26y^2 + 25 = 0

    I know how to factor but this one is throwing me off...
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Aug 2007
    Posts
    144
    Hi civiliam,

    We have y^4-26y^2+25=0 . Notice that this is a quadratic in y^2 , thus if we let w=y^2 we can re-write the equation as w^2-26w+25=0 . Now this is a fairly routine quadratic since w^2-26w+25=(w-25)(w-1)=0 and thus we can conclude that w=25 , w=1 . Since w=y^2 we can say y^2=25 , y^2=1 and therefore the four roots of the equation are \pm 5 , \pm 1 .

    Hope this helps.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Oct 2008
    Posts
    26
    thank you so much that's perfect
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Need help factoring a question.
    Posted in the Algebra Forum
    Replies: 4
    Last Post: April 20th 2011, 11:06 PM
  2. Factoring Question
    Posted in the Algebra Forum
    Replies: 3
    Last Post: April 23rd 2010, 04:12 PM
  3. Factoring question
    Posted in the Algebra Forum
    Replies: 5
    Last Post: January 31st 2010, 02:33 PM
  4. Question on Factoring
    Posted in the Algebra Forum
    Replies: 9
    Last Post: May 30th 2008, 11:55 AM
  5. Factoring question
    Posted in the Algebra Forum
    Replies: 3
    Last Post: March 27th 2007, 10:58 AM

Search Tags


/mathhelpforum @mathhelpforum