(4-x^2)^(1/2) + (1/2(4-x^2)^(-1/2)) (-2x) Stuck on my calculus trying to simplify this algebra *sigh*...
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Is this what it looks like? $\displaystyle \sqrt{4-x^2} -\frac{2x}{2\sqrt{4-x^2}}$
Originally Posted by 11rdc11 Is this what it looks like? $\displaystyle \sqrt{4-x^2} -\frac{2x}{2\sqrt{4-x^2}}$ yes
$\displaystyle \sqrt{4-x^2} -\frac{2x}{2\sqrt{4-x^2}}$ 1st cancel out the 2 $\displaystyle \sqrt{4-x^2} -\frac{x}{\sqrt{4-x^2}}$ Next find common denominator $\displaystyle \frac{-x^2 -x+4}{\sqrt{4-x^2}}$ Next rationlize
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