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Thread: logarithm problem

  1. September 30th 2008, 04:21 PM #1
    Shadowfox1
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    logarithm problem

    Here is the problem: e^(x+3) = (e^x) + 1

    I use ln and get it to look like this: x + 3 = x but then what is the answer?
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  2. September 30th 2008, 04:45 PM #2
    Jameson
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    Not quite right.

    Look at it this way.

    e^{x+3}-e^x = 1

    e^{x}*e^3 - e^x=1

    e^x(e^3 - 1)=1

    e^x= \frac{1}{e^3 -1}

    Got it from here?
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  3. September 30th 2008, 05:02 PM #3
    Shadowfox1
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    o wow. I didn't even think to do that. thanks a lot.
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