Thread: algebra word problem

alice invested a portion of $500 at 4% interest and the remainder at 5%.
how much did she invest at each rate if her total income from both investments is $23.28.

Originally Posted by watsod8

alice invested a portion of $500 at 4% interest and the remainder at 5%.
how much did she invest at each rate if her total income from both investments is $23.28.

Let x = amout invested at 4%

Let 500 - x = amount invested at 5%

.04x + .05(500 - x) = 23.28

Finish up....good luck.

Originally Posted by watsod8

alice invested a portion of $500 at 4% interest and the remainder at 5%.
how much did she invest at each rate if her total income from both investments is $23.28.

Let x denote the amount which is invested at 4%, then (500-x) are invested at 5%:



Solve for x. I've got $162

Hi,

I tried to solve this and I don't get $162 . can someone please check my working and tell me were I have gone wrong .

thank you











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Originally Posted by earboth

Let x denote the amount which is invested at 4%, then (500-x) are invested at 5%:



Solve for x. I've got $162

Typo, Earboth, but setup is good. Investment at 4% = $172

I don't get $172. were have I gone wrong?

Originally Posted by Tweety

Hi,

I tried to solve this and I don't get $162 . can someone please check my working and tell me were I have gone wrong .

thank you



First, it's 23.28, not 23.38

Second, 4%=.04 and 5%=.05









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Corrections in red.