Originally Posted by

**Alienis Back** Find two values of b that will make [tex]9x^2+bx+25[tex] a perfect square trinomial.

The formulas for Perfect Square Trinomial are:

[tex](a+b)^2=a^2+2ab+b^2[tex]

[tex](a-b)^2=a^2-2ab+b^2[tex]

As I solved:

[tex]9x^2+bx+25[tex]

[tex](3x)^2+2(3x)(5)+5^2[tex]

[tex]9x^2+6x(5)+25[tex]

[tex]9x^2+30x+25[tex]

Then...according to this one of those two values would be 30 but I'm not sure about it for I didn't find anything. I just replaced the given values [tex]9x^2[tex] and [tex]25[tex] into the middle term of the formula. And I couldn't find the other number.