1. ## Functions help!!!!

1)Use transformations to plot $y=3f[-1/2(x+1)]-4$ given that $f(x)=lxl$

2) For the function defined by $f(x)=-x^3-3$, determine the inverse

3) Determine equations for 2 functions on graph. And also state the Domain and Range

And sketch the inverse

1)Use transformations to plot $y=3f[-1/2(x+1)]-4$ given that $f(x)=lxl$
see post #4 here

2) For the function defined by $f(x)=-x^3-3$, determine the inverse
write $y = -x^3 - 3$

now, switch $x$ and $y$ and solve for $y$. this will give you the inverse function

3) Determine equations for 2 functions on graph. And also state the Domain and Range

And sketch the inverse
your graph, at least to me, is not accurate enough to know what the formulas are. the somewhat curvy part looks like $2 \sqrt{x + 1}$. the other part however, i would do it using two straight lines. the question makes me think this is a single graph though, and so, i am thinking some shifted |x| graph. perhaps -|x + 5| + 6. but this doesn't fit all the characteristics, namely, the x-intercepts.

so this function is piecewise defined.

anyway, for the inverse function, draw (faintly) the line y = x and reflect the graph in it

the domain is the set of x-values for which the function is defined and the range is the set of y-values for which the function is defined.

3. For the first one. I need to see the graph. Would it be possiable for you to fraw it for me?

For the second one, so would it be?
$
y=-x^3-3
$

$
x=-y^3-3
$

$
y^3=x-3
$

how would I finish it?

And for the third one. What would also be my D and R?

For the first one. I need to see the graph. Would it be possiable for you to fraw it for me?
i gave you the rules you need to draw it on your own

For the second one, so would it be?
$
y=-x^3-3
$

$
x=-y^3-3
$

$
y^3=x-3
$

how would I finish it?
take the cube root of both sides (what you have is wrong, by the way. why is the x positive?)

And for the third one. What would also be my D and R?
i told you how to find those, i won't do it for you. read what i said and think about it