1. ## "story/word problem"

Here's the story:
a girl bikes home. 2/3 way there, the bike gets a flat tire, so the remaining 1/3 of the distance, she walks. it takes her twice as long to walk as it does to bike. How many times faster is her speed when biking than when walking?

I am wondering how YOU would set up and solve this problem. I got my answer but want to see how YOU approach a problem like this.

Thanks. I'm learning how to do word problems faster . I'm really "poor" at them.

2. I see that she traveled twice as far (2/3 of the distance vs. 1/3 of the distance) in half the time. That translates to speed four time greater on the bike ...

(2 times farther)/(1/2 the time) = 2(2/1) = 4 times faster

3. ## another way to think it

Originally Posted by skeeter
I see that she traveled twice as far (2/3 of the distance vs. 1/3 of the distance) in half the time. That translates to speed four time greater on the bike ...

(2 times farther)/(1/2 the time) = 2(2/1) = 4 times faster
So let x be the distance traveled by walking
2x is distance traveled by bike.
t= time wlking
1/2 = time bking

speed walking = d/t = 2x/ (1/2t) = 4 x/t
4 times the walking speed