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Math Help - "story/word problem"

  1. #1
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    "story/word problem"

    Here's the story:
    a girl bikes home. 2/3 way there, the bike gets a flat tire, so the remaining 1/3 of the distance, she walks. it takes her twice as long to walk as it does to bike. How many times faster is her speed when biking than when walking?

    I am wondering how YOU would set up and solve this problem. I got my answer but want to see how YOU approach a problem like this.

    Thanks. I'm learning how to do word problems faster . I'm really "poor" at them.
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  2. #2
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    I see that she traveled twice as far (2/3 of the distance vs. 1/3 of the distance) in half the time. That translates to speed four time greater on the bike ...

    (2 times farther)/(1/2 the time) = 2(2/1) = 4 times faster
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  3. #3
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    another way to think it

    Quote Originally Posted by skeeter View Post
    I see that she traveled twice as far (2/3 of the distance vs. 1/3 of the distance) in half the time. That translates to speed four time greater on the bike ...

    (2 times farther)/(1/2 the time) = 2(2/1) = 4 times faster
    So let x be the distance traveled by walking
    2x is distance traveled by bike.
    t= time wlking
    1/2 = time bking

    speed walking = d/t = 2x/ (1/2t) = 4 x/t
    4 times the walking speed
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