This is a really silly question, but I can't seem to do it.
How do I rearrange
$\displaystyle 1000x + 221 \:=\:x\!\cdot\!y $
into
$\displaystyle
x \;=\;\frac{221}{y-1000}
$
Thanks
This is a really silly question, but I can't seem to do it.
How do I rearrange
$\displaystyle 1000x + 221 \:=\:x\!\cdot\!y $
into
$\displaystyle
x \;=\;\frac{221}{y-1000}
$
Thanks
Get terms that contain an x on one side and leave everything else on the other side.
$\displaystyle 1000x+221=xy\implies 221=xy-1000x$
Now on the right side, there is a common factor of $\displaystyle x$.
Thus $\displaystyle 221=xy-1000x\implies 221=(y-1000)x$
Can you take it from here?
--Chris