1. ## Rearranging an equation

This is a really silly question, but I can't seem to do it.

How do I rearrange
$1000x + 221 \:=\:x\!\cdot\!y$

into
$
x \;=\;\frac{221}{y-1000}
$

Thanks

2. Originally Posted by BG5965
This is a really silly question, but I can't seem to do it.

How do I rearrange
$1000x + 221 \:=\:x\!\cdot\!y$

into
$
x \;=\;\frac{221}{y-1000}
$

Thanks
Get terms that contain an x on one side and leave everything else on the other side.

$1000x+221=xy\implies 221=xy-1000x$

Now on the right side, there is a common factor of $x$.

Thus $221=xy-1000x\implies 221=(y-1000)x$

Can you take it from here?

--Chris

3. Yes I can, thankyou so much.