hey i was wondering if anyone could help me solve this equation for X.
a=1/1+x
It's so simple.
$\displaystyle a=\frac{1}{1+x}\text{ for }x\neq-1$, we have $\displaystyle x+1=\frac{1}{a}$, which gives $\displaystyle x=\frac{1}{a}-1=\frac{1-a}{a}$.
Note that $\displaystyle a=0$ if $\displaystyle |x|\to\infty$.
However, this can not hold for any finite value of $\displaystyle x$.
Hi caligyrl4lyfe,
We have $\displaystyle a=\frac{1}{1+x}$ . Multiplying both sides by $\displaystyle 1+x$ yields $\displaystyle a(1+x)=1$ . Now expanding the bracket gives $\displaystyle a+ax=1$ . Minusing the $\displaystyle a$ from both sides then dividing through by $\displaystyle a$ leads to $\displaystyle x=\frac{1-a}{a}$ . Which alternatively can be written as $\displaystyle x=\frac{1}{a}-1$ .
Hope this helps.