find the solution sets 4x^2 + 9y^2 = 25 3y + 2x = 1
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Originally Posted by eepyej find the solution sets 4x^2 + 9y^2 = 25 3y + 2x = 1 Have you tried this yourself yet? Hint: Get the second equation as y in terms of x or vice versa. Substitute into the first equation.
Hi eepyej From ur second equation make either x or y the subject of formula as Prove It told,... 3y+2x=1 => 2x=1-3y => x=(1-3y)/2 Then substitute this x in the first equation, u will get a quadratic equation in terms of y only, solve it
Originally Posted by eepyej find the solution sets 4x^2 + 9y^2 = 25 3y + 2x = 1 Originally Posted by Kai Hi eepyej From ur second equation make either x or y the subject of formula as Prove It told,... 3y+2x=1 => 2x=1-3y => x=(1-3y)/2 Then substitute this x in the first equation, u will get a quadratic equation in terms of y only, solve it Or you can do it in a way to avoid fractions! $\displaystyle 4x^2 + 9y^2 = 25\implies (2x)^2+(3y)^2=25$ $\displaystyle 3y + 2x = 1$ You can solve for either 2x or 3y, and then substitute --Chris
Nice, didnt see it
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