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Math Help - solution sets

  1. #1
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    solution sets

    find the solution sets

    4x^2 + 9y^2 = 25
    3y + 2x = 1
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  2. #2
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    Quote Originally Posted by eepyej View Post
    find the solution sets

    4x^2 + 9y^2 = 25
    3y + 2x = 1
    Have you tried this yourself yet?

    Hint: Get the second equation as y in terms of x or vice versa. Substitute into the first equation.
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  3. #3
    Kai
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    Hi eepyej

    From ur second equation make either x or y the subject of formula as Prove It told,... 3y+2x=1
    => 2x=1-3y
    => x=(1-3y)/2

    Then substitute this x in the first equation, u will get a quadratic equation in terms of y only, solve it
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  4. #4
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by eepyej View Post
    find the solution sets

    4x^2 + 9y^2 = 25
    3y + 2x = 1
    Quote Originally Posted by Kai View Post
    Hi eepyej

    From ur second equation make either x or y the subject of formula as Prove It told,... 3y+2x=1
    => 2x=1-3y
    => x=(1-3y)/2

    Then substitute this x in the first equation, u will get a quadratic equation in terms of y only, solve it

    Or you can do it in a way to avoid fractions!

    4x^2 + 9y^2 = 25\implies (2x)^2+(3y)^2=25
    3y + 2x = 1

    You can solve for either 2x or 3y, and then substitute

    --Chris
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  5. #5
    Kai
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    Smile

    Nice, didnt see it
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