Yes Jhevon,x= 3+ ln[y/1-y],iswhat I was trying to write, sorry I am new to
posting on forums, but will try to get the hang of it. Hope you can help.
but yes, you are right so far. now expand the brackets
you think you can take it from here? remember, to solve for we need to get all 's on one side of the equation. then see if we can get to a kind of format