(-1 minus √-80) minus (3 + √-20)
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Originally Posted by blame_canada100 (-1 minus √-80) minus (3 + √-20) $\displaystyle (-1 - \sqrt{-80}) - (3 + \sqrt{-20}) = (-1 - i\sqrt{80}) - (3 + i\sqrt{20})$ $\displaystyle = (-1 - i4\sqrt{5}) - (3 + i2\sqrt{5})$ $\displaystyle = -1 - 3 - i4\sqrt{5} - i2\sqrt{5} $ $\displaystyle = -4 - i6\sqrt{5} $
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