29- { 5+3 [ 8 x (10 - 8 ) ] -50 }
I do not understand this. This is not offical homework, but I don't want to get behind. Also what do these { } mean
They are just another way of expressing paranthesis.
Something written like this doesn't look very good.
$\displaystyle (5+(((2*3)-1)+7^3)-1)$ Woah!
So we use other kind of brackets sometimes.
Now to your question.
You have:{ 5+3 [ 8 x (10 - 8 ) ] -50 }
Use PEMDAS or order of operations
1. $\displaystyle {5+3[8 \times (10-8) ] -50}$
2. $\displaystyle {5+3[8 \times (2)] -50}$
3. $\displaystyle {5+3[16]-50$
4. $\displaystyle {5+48-50}$
5. $\displaystyle 3$ There's your answer!
Of course, considering barbienut doesn't know greatest integers and divine sets (neither do I for that matter) I don't think it's really relevant what you thinkOriginally Posted by ThePerfectHacker
although, I personally agree with you. I think it's sort of fun (although I don't think anyone else agrees with my) to figure out which paranthesis pair up. I've also become good at it by using excel.
Hello, barbienut75!
I have questions about what you wrote . . .
. . . . . . . . I assume this is "times"
. . . . . . . . . . . . . . $\displaystyle \downarrow$
. . . 29 - { 5 + 3 [ 8 x (10 - 8 ) ] - 50 }
. . . . . . . . . . . $\displaystyle \uparrow$
. . . . . . . but is this also "times"?
If so, I can explain the procedure.
Start within the "innermost" grouping symbols.
We have: .$\displaystyle 29 - \bigg(5 \:+ \:3\cdot[8\cdot\underbrace{(10 - 8)}] \:- \:50\bigg) $
. . . . . . . . . . . . . . . . . . . . . .$\displaystyle \downarrow$
. . . . . .$\displaystyle = \;29 \,- \,\bigg(5 \;\;\;+ \;\;\;3\cdot\underbrace{[8\cdot2]} \;\;- \;\;50 \bigg)$
. . . . . . . . . . . . . . . . . . . . .$\displaystyle \downarrow$
. . . . . .$\displaystyle = \;29 \:- \:\bigg(5 \quad+ \quad\underbrace{3\cdot16}\quad- \quad 50\bigg) $
. . . . . . . . . . . . . . . . . . . .$\displaystyle \downarrow$
. . . . . .$\displaystyle = \;29 \:- \:\underbrace{\bigg(5 \quad + \quad\;\;48\quad\;\; - \quad50\bigg)}$
. . . . . . . . . . . . . . . . . . . . $\displaystyle \downarrow$
. . . . . .$\displaystyle = \qquad\underbrace{29 \qquad\, - \,\qquad 3} $
. . . . . .$\displaystyle = \;\qquad\qquad\;\;\boxed{26} $