29- { 5+3 [ 8 x (10 - 8 ) ] -50 } :eek:

I do not understand this. This is not offical homework, but I don't want to get behind. Also what do these { } mean

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- Aug 21st 2006, 03:58 PMbarbienut75Hello, newbie needs help.
29- { 5+3 [ 8 x (10 - 8 ) ] -50 } :eek:

I do not understand this. This is not offical homework, but I don't want to get behind. Also what do these { } mean - Aug 21st 2006, 04:07 PMJameson
They are just another way of expressing paranthesis.

Something written like this doesn't look very good.

$\displaystyle (5+(((2*3)-1)+7^3)-1)$ Woah!

So we use other kind of brackets sometimes.

Now to your question.

You have:{ 5+3 [ 8 x (10 - 8 ) ] -50 }

Use PEMDAS or order of operations

1. $\displaystyle {5+3[8 \times (10-8) ] -50}$

2. $\displaystyle {5+3[8 \times (2)] -50}$

3. $\displaystyle {5+3[16]-50$

4. $\displaystyle {5+48-50}$

5. $\displaystyle 3$ There's your answer! :) - Aug 21st 2006, 04:17 PMbarbienut75
What about the 29-

29-{ 5+3 [ 8 x (10 - 8 ) ] -50 } - Aug 21st 2006, 04:52 PMJameson
Ooops! Didn't see that. Then it's 29-3=26

- Aug 21st 2006, 05:08 PMQuick
I would just like to point out Jameson, that you can wright brackets with Latex:

$\displaystyle \{ 5+3 [ 8 x (10 - 8 ) ] -50 \}$ - Aug 21st 2006, 06:28 PMThePerfectHacker
I my self prefer to use the singe parantheses, ( )

The other [ ] can be confused with greatest integer function.

And never try to use { } because it deals with sets which are divine. - Aug 21st 2006, 06:52 PMQuickQuote:

Originally Posted by**ThePerfectHacker**

*you*think :eek:

although, I personally agree with you. I think it's sort of fun (although I don't think anyone else agrees with my) to figure out which paranthesis pair up. I've also become good at it by using excel. - Aug 22nd 2006, 07:05 PMSoroban
Hello, barbienut75!

I have questions about what you wrote . . .

. . . . . . . . I assume this is "times"

. . . . . . . . . . . . . . $\displaystyle \downarrow$

. . . 29 - { 5 + 3 [ 8 x (10 - 8 ) ] - 50 }

. . . . . . . . . . . $\displaystyle \uparrow$

. . . . . . . but is this also "times"?

If so, I can explain the procedure.

Start within the "innermost" grouping symbols.

We have: .$\displaystyle 29 - \bigg(5 \:+ \:3\cdot[8\cdot\underbrace{(10 - 8)}] \:- \:50\bigg) $

. . . . . . . . . . . . . . . . . . . . . .$\displaystyle \downarrow$

. . . . . .$\displaystyle = \;29 \,- \,\bigg(5 \;\;\;+ \;\;\;3\cdot\underbrace{[8\cdot2]} \;\;- \;\;50 \bigg)$

. . . . . . . . . . . . . . . . . . . . .$\displaystyle \downarrow$

. . . . . .$\displaystyle = \;29 \:- \:\bigg(5 \quad+ \quad\underbrace{3\cdot16}\quad- \quad 50\bigg) $

. . . . . . . . . . . . . . . . . . . .$\displaystyle \downarrow$

. . . . . .$\displaystyle = \;29 \:- \:\underbrace{\bigg(5 \quad + \quad\;\;48\quad\;\; - \quad50\bigg)}$

. . . . . . . . . . . . . . . . . . . . $\displaystyle \downarrow$

. . . . . .$\displaystyle = \qquad\underbrace{29 \qquad\, - \,\qquad 3} $

. . . . . .$\displaystyle = \;\qquad\qquad\;\;\boxed{26} $