# Math Help - Inverse of this function...

1. ## Inverse of this function...

y=2e^(-x)

Is it
y=ln(2/x) ?

2. $y = -\ln\bigg(\frac{x}{2}\bigg)$

3. Are they the same?

If x=2,
y=2e^(-2)=0.2706

So for the inverse, if x=0.2706
y=-ln(0.2706/2)=2
and
y=ln(2/0.2706)=2

Am I correct in saying that the two functions (y=-ln(x/2) and y=ln(2/x)) are the same?

4. Yep its the same

5. Originally Posted by MegaVortex7
Am I correct in saying that the two functions (y=-ln(x/2) and y=ln(2/x)) are the same?
i just want to clarify 11rdc11's response

recall: $\log_a (x^n) = n \log_a x$

so $- \ln \bigg( \frac x2 \bigg) = \ln \bigg( \frac x2 \bigg)^{-1} = \ln \bigg( \frac 2x \bigg)$