The function h(x) =3(x-3)(x+2)(x-5) is translated 4 units to the left and 5 units down. Write an equation for the transformed function. How do I get this function into y = a [ k (x - d) ] ^n + c format? Or is there another way?
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Originally Posted by B-lap The function h(x) =3(x-3)(x+2)(x-5) is translated 4 units to the left and 5 units down. Write an equation for the transformed function. How do I get this function into y = a [ k (x - d) ] ^n + c format? Or is there another way? h(x) --> g(x) = h(x + 4) - 5.
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