Please help!!
x^2+2px+(3p+4)=0 , where p is a positive constant, has equal roots
a) Find the value of p.
b) for this value of p, solve the equation.
An equation has repeating [equal] roots when the discriminant is equal to zero.
$\displaystyle \Delta=b^2-4ac\implies \Delta=(2p)^2-4(1)(3p+4)=4p^2-12p-16$
Thus, $\displaystyle \Delta=0$ when $\displaystyle 4p^2-12p-16=0\implies p^2-3p-4=0$
Can you take it from here and solve for $\displaystyle p$?
--Chris