Please help!! x^2+2px+(3p+4)=0 , where p is a positive constant, has equal roots a) Find the value of p. b) for this value of p, solve the equation.
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Greetings, First of all, think when quadratic equations have equal roots. From there you get two values for p, one of which is negative and solving the equation with the other p is not a problem, I shall assume.
Originally Posted by randomised Please help!! x^2+2px+(3p+4)=0 , where p is a positive constant, has equal roots a) Find the value of p. b) for this value of p, solve the equation. An equation has repeating [equal] roots when the discriminant is equal to zero. Thus, when Can you take it from here and solve for ? --Chris
Originally Posted by randomised Please help!! x^2+2px+(3p+4)=0 , where p is a positive constant, has equal roots a) Find the value of p. b) for this value of p, solve the equation. Set the discriminant to zero for a double root. a = 1 b = 2p c = 3p + 4 Geeze! Way too slow today!
Perhaps D = k^2 - ac, k = b/2 would shorten the path.
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