Square root(x^2 y^4 z^8) how do you simplify something like this????
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Originally Posted by chinese_man_77 Square root(x^2 y^4 z^8) how do you simplify something like this???? All the terms in the square root are multiplied and they are squares. That means you can do some cancellation. $\displaystyle \sqrt{x^2 y^4 z^8}=\sqrt{(x)^2 (y^2)^2 (z^4)^2} = \sqrt{(x y^2 z^4)^2} = x y^2 z^4$
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