I have a question in which I have to rationalize the numerator but then I end up with radicals in the denominator. It almost seems like a lose-lose:

square root of (x + h) - square root of (x) all divided by h

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- Sep 23rd 2008, 10:09 AMcjh824Rationalizing Numerator
I have a question in which I have to rationalize the numerator but then I end up with radicals in the denominator. It almost seems like a lose-lose:

square root of (x + h) - square root of (x) all divided by h - Sep 23rd 2008, 10:20 AM11rdc11
$\displaystyle \frac{\sqrt{x+h} - \sqrt{x}}{h}$

$\displaystyle \bigg(\frac{\sqrt{x+h} - \sqrt{x}}{h}\bigg)\bigg(\frac{\sqrt{x+h} + \sqrt{x}}{\sqrt{x+h} + \sqrt{x}}\bigg)$

$\displaystyle \frac{x+h -x}{h(\sqrt{x+h} + \sqrt{x})}$

$\displaystyle \frac{1}{\sqrt{x+h} + \sqrt{x}}$

What you doing is taking the derivative of $\displaystyle \sqrt{x}$ - Sep 23rd 2008, 10:22 AMJameson
^ That's exactly how it's done. You have to have radicals either in the numerator or denominator here, you just can't cancel them. You're right that it is standard convention to not leave any radicals in the denominator but since your question specifically says rationalize the numerator, rules must be bent.

- Sep 23rd 2008, 10:24 AMcjh824
So it is okay to have radicals in the denominator. That is what I got I just wasn't sure if I had to rationalize it again or something. Thanks a lot!