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Math Help - Radical

  1. #1
    Junior Member
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    Radical

    I am multiplying radicals and I have a question like this:

    square root of ((6x^7)(y^3)) multiplied by square root of ((7x^3)(y^-1))

    In the end I got x^(5)y(square root of 42)

    Does this look right at all?
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  2. #2
    MHF Contributor kalagota's Avatar
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    Quote Originally Posted by cjh824 View Post
    I am multiplying radicals and I have a question like this:

    square root of ((6x^7)(y^3)) multiplied by square root of ((7x^3)(y^-1))

    In the end I got x^(5)y(square root of 42)

    Does this look right at all?
    yes, that is fine..
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  3. #3
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    Hello, cjh824!

    Simplify: . \sqrt{6x^7y^3}\cdot\sqrt{7x^3y^{-1}}

    In the end I got: . x^5y\sqrt{42} . . . . Right!

    \sqrt{6x^7y^3}\cdot\sqrt{7x^3y^{-1}} \;=\;\sqrt{(6x^7y^3)(7x^3y^{-1})}

    . . =\;\sqrt{42x^{10}y^2} \;=\;\sqrt{42}\cdot\sqrt{x^{10}}\cdot\sqrt{y^2} \;=\;x^5y\sqrt{42}

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  4. #4
    MHF Contributor kalagota's Avatar
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    in addition, it should be true in the assumption that x and y are non negative or both negative..

    simply stated, x and y should have the same sign..
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