please help

josiemosie · August 18th 2006, 07:46 PM

i need help with this problem.

6 3/6=39/6

how to do this?

**rgep** · August 18th 2006, 11:16 PM

6 3/6 is "six and three-sixths", or "6 ones plus 3 sixths". You want to get this as a number of sixths. Since a one is 6 sixths, the 6 ones are 6 times 6 sixths. So you have 6 times 6 sixths plus 3 sixths, that is, 36 sixths plus 3 sixths, or 39 sixths, which is just 39/6.

**Quick** · August 19th 2006, 03:58 AM

Originally Posted by josiemosie

i need help with this problem.

6 3/6=39/6

how to do this?

Since rgep's post is a tongue-twister (and since I haven't answered in a while), I shall reexplain.

we have: $6+\frac{3}{6}$

which you can change to: $\overbrace{(36\div 6)}^{\text{notice this equals six}}+\frac{3}{6}$

then we turn it into a fraction: $\frac{36}{6}+\frac{3}{6}$

now we add them together: $\frac{36+3}{6}$

and so we get: $\frac{39}{6}$

**galactus** · August 19th 2006, 04:42 AM

To change $a\frac{b}{c}$ to a improper fraction multiply a times c and add b, all over c

For instance, in yours, a=6, b=3, c=6

6*6+3=39; all over c: 39/6

Which reduces to 13/2.

**Soroban** · August 19th 2006, 06:44 AM

Hello, josiemosie!

Where did this problem come from?
It is very strangely written . . .

$6\,\frac{3}{6}\;=\;\frac{39}{6}$

The truth is: . $6\frac{3}{6}\:=\:\boxed{\frac{13}{2}}$ . . . Who leaves their fractions unreduced??

Why didn't they start with $6\frac{1}{2}$ and simplify to $\frac{13}{2}$ ?

If we're not supposed to reduce our fractions, we can have:

. . Show that: . $1\frac{300}{500} \:=\:\frac{13,840}{8,650}$ . . . It makes as much sense.

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