i need help with this problem.

6 3/6=39/6

how to do this?

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- Aug 18th 2006, 07:46 PMjosiemosieplease help
i need help with this problem.

6 3/6=39/6

how to do this? - Aug 18th 2006, 11:16 PMrgep
6 3/6 is "six and three-sixths", or "6 ones plus 3 sixths". You want to get this as a number of sixths. Since a one is 6 sixths, the 6 ones are 6 times 6 sixths. So you have 6 times 6 sixths plus 3 sixths, that is, 36 sixths plus 3 sixths, or 39 sixths, which is just 39/6.

- Aug 19th 2006, 03:58 AMQuickQuote:

Originally Posted by**josiemosie**

we have: $\displaystyle 6+\frac{3}{6}$

which you can change to: $\displaystyle \overbrace{(36\div 6)}^{\text{notice this equals six}}+\frac{3}{6}$

then we turn it into a fraction: $\displaystyle \frac{36}{6}+\frac{3}{6}$

now we add them together: $\displaystyle \frac{36+3}{6}$

and so we get: $\displaystyle \frac{39}{6}$ - Aug 19th 2006, 04:42 AMgalactus
To change $\displaystyle a\frac{b}{c}$ to a improper fraction multiply a times c and add b, all over c

For instance, in yours, a=6, b=3, c=6

6*6+3=39; all over c: 39/6

Which reduces to 13/2. - Aug 19th 2006, 06:44 AMSoroban
Hello, josiemosie!

Where did this problem come from?

It isstrangely written . . .*very*

Quote:

$\displaystyle 6\,\frac{3}{6}\;=\;\frac{39}{6}$

The truth is: .$\displaystyle 6\frac{3}{6}\:=\:\boxed{\frac{13}{2}}$ . . .*Who*leaves their fractions unreduced??

Why didn't they start with $\displaystyle 6\frac{1}{2}$ and simplify to $\displaystyle \frac{13}{2}$ ?

If we're**not**supposed to reduce our fractions, we can have:

. . Show that: .$\displaystyle 1\frac{300}{500} \:=\:\frac{13,840}{8,650}$ . . . It makes as much sense.