i need help with this problem.

6 3/6=39/6

how to do this?

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- August 18th 2006, 08:46 PMjosiemosieplease help
i need help with this problem.

6 3/6=39/6

how to do this? - August 19th 2006, 12:16 AMrgep
6 3/6 is "six and three-sixths", or "6 ones plus 3 sixths". You want to get this as a number of sixths. Since a one is 6 sixths, the 6 ones are 6 times 6 sixths. So you have 6 times 6 sixths plus 3 sixths, that is, 36 sixths plus 3 sixths, or 39 sixths, which is just 39/6.

- August 19th 2006, 04:58 AMQuickQuote:

Originally Posted by**josiemosie**

we have:

which you can change to:

then we turn it into a fraction:

now we add them together:

and so we get: - August 19th 2006, 05:42 AMgalactus
To change to a improper fraction multiply a times c and add b, all over c

For instance, in yours, a=6, b=3, c=6

6*6+3=39; all over c: 39/6

Which reduces to 13/2. - August 19th 2006, 07:44 AMSoroban
Hello, josiemosie!

Where did this problem come from?

It isstrangely written . . .*very*

Quote:

The truth is: . . . .*Who*leaves their fractions unreduced??

Why didn't they start with and simplify to ?

If we're**not**supposed to reduce our fractions, we can have:

. . Show that: . . . . It makes as much sense.