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Math Help - Question with roots.indexes, etc. So confusing for homework pass-in.

  1. #1
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    Question with roots.indexes, etc. So confusing for homework pass-in.

    The question goes a little something like this, and sorry if it`s confusing:

    (Square root of x^3)times (index of 5, square root of x^6)

    all divided by (index of 15, square root of x^3)

    Any help would be so greatly appreciated. Thanks a million!
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  2. #2
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    skeeter's Avatar
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    is this what you mean?

    \frac{\sqrt{x^3} \cdot \sqrt[5]{x^6}}{\sqrt[15]{x^3}}
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  3. #3
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    Yep! That's exactly what I mean!
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  4. #4
    Super Member 11rdc11's Avatar
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    Think of it like this

    \frac{(x^{\frac{3}{2}})(x^{\frac{6}{5}})}{x^{\frac  {3}{15}}}

    add the exponents in the numerator since it to the same base

    \frac{x^{\frac{27}{10}}}{x^{\frac{3}{15}}}

    then bring the power in the denominator to the top

    and you end up with

    x^{\frac{15}{6}}
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  5. #5
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    Quote Originally Posted by cjh824 View Post
    The question goes a little something like this, and sorry if it`s confusing:

    (Square root of x^3)times (index of 5, square root of x^6)

    all divided by (index of 15, square root of x^3)

    Any help would be so greatly appreciated. Thanks a million!
    further,

    = x^{\frac{5}{3}}=x \sqrt[3] {x^2}
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  6. #6
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by Shyam View Post
    further,

    = x^{\frac{5}{3}}=x \sqrt[3] {x^2}
    That should be

    = x^{\frac{5}{2}}= x^2\sqrt{x}
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