1. ## Algebra word problem

I have a word problem that I know the answer is supposed to be 5 liters, however, that is not the answer I'm getting when I solve it. Can anyone help?

Word problem: It is necessary to have a 40% antifreeze solution in the radiator of a certain car. The radiator now holds 20 liters of 20% solution. How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength? (Hint: the number of liters drained is equal to the number of liters replaced.)

This is the formula I am using, of course, maybe this is my problem.

.20 (20) - .20x + 1.0 (x) = .40 (20)

2. The key is that the total amount of liquid is still going to be equal to 20 liters in the end, so the final 40% solution will contain 8 liters of antifreeze.

Let's say that x is the amount of 100% solution you replace the 20% solution with.

So you want .2(20 - x) + x = 8. Just solve for x. Edit: this is the same as you came up with, and the answer is indeed 5. Perhaps your calculations went awry?