http://i125.photobucket.com/albums/p...itty/sde-1.jpg

Could someone try to explain if it does? Thank you

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- Sep 22nd 2008, 02:51 PMHawthorneKittyDoes this Make sense?
http://i125.photobucket.com/albums/p...itty/sde-1.jpg

Could someone try to explain if it does? Thank you

- Sep 22nd 2008, 03:11 PMicemanfan
Try using powers in parentheses. This expression is equivalent to

$\displaystyle ((a/b) \cdot x)^{1/2}$

where

$\displaystyle x = ((b/a) \cdot (a/b)^{1/2})^{1/2}$.

Let's evaluate x.

$\displaystyle x = ((a/b)^{-1} \cdot (a/b)^{1/2})^{1/2}$

$\displaystyle x = ((a/b)^{-1/2})^{1/2}$

$\displaystyle x = (a/b)^{-1/4}$

Now for the original expression:

$\displaystyle ((a/b) \cdot (a/b)^{-1/4})^{1/2}$

$\displaystyle ((a/b)^{3/4})^{1/2}$

$\displaystyle (a/b)^{3/8}$

Hence k = 3/8.