The sum of the squares of two consecutive odd integers is 290. Find the integers. I need help on this question.
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Set up an equation for the info given. $\displaystyle n^2 + (n + 2)^2 = 290$ Solve the equation and it will give you 11 and -13 so one solution is 11 and 13 and the other is -11 and -13
Originally Posted by andrewpark2 The sum of the squares of two consecutive odd integers is 290. Find the integers. I need help on this question. Let the integers be 2x - 1 and 2x + 1. Solve for x: $\displaystyle (2x-1)^2 + (2x+1)^2 = 290$.
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