1. word problem

The sum of the squares of two consecutive odd integers is 290. Find the integers. I need help on this question.

2. Set up an equation for the info given.

$n^2 + (n + 2)^2 = 290$

Solve the equation and it will give you 11 and -13

so one solution is 11 and 13 and the other is -11 and -13

3. Originally Posted by andrewpark2
The sum of the squares of two consecutive odd integers is 290. Find the integers. I need help on this question.
Let the integers be 2x - 1 and 2x + 1.

Solve for x: $(2x-1)^2 + (2x+1)^2 = 290$.