Hi, I need help on the following problem:
If $\displaystyle \frac{(2y+2z-x)}{a} = \frac{(2z+2x-y)}{b} = \frac{(2x+2y-z)}{c} $ show that: $\displaystyle \frac{x}{(2b+2c-a)} = \frac{y}{(2c+2a-b)} = \frac{z}{(2a+2b-c)} $
Any hints will help, thanks.
Hi, I need help on the following problem:
If $\displaystyle \frac{(2y+2z-x)}{a} = \frac{(2z+2x-y)}{b} = \frac{(2x+2y-z)}{c} $ show that: $\displaystyle \frac{x}{(2b+2c-a)} = \frac{y}{(2c+2a-b)} = \frac{z}{(2a+2b-c)} $
Any hints will help, thanks.