You did it right. That's the x.
As for the trial x = 0.032, it does revert back correctly also. Do it it very carefully. It checks.
Any help welcome!!
I am trying to re arrange the following regression equation to find out x as I have a value for y.
Log10(y)= - 2.780+0.470(LOG10(x))
I rearranged it as this below but it does not seem to work please can you let me know where I have gone wrong:
x = 10^(LOG10y +2.780)/0.470)
Is this right? I donít think so as if I put in an imaginary number in for X (0.032) in first equation and then get a value of y, when I try to used the new value of y in my lower equation I donít get back to my original value of X?