How do i factor this? 1331x^9 + 343y^6
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Sum of cubes? $\displaystyle \left( {11x^3 + 7y^2 } \right)\left( {121x^6 - 77x^3 y^2 + 49y^4 } \right)$
sum of two cubes factors as shown ... $\displaystyle a^3 + b^3 = (a+b)(a^2 - ab + b^2)$ now note that ... $\displaystyle 1331x^9 + 343y^6 = (11x^3)^3 + (7y^2)^3$
Can you show how its done?
ok
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