(sqroot(x^3+x^2))/x Anyone know how to simplify this?
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Originally Posted by gearshifter (sqroot(x^3+x^2))/x Anyone know how to simplify this? If this is what you wrote: $\displaystyle \frac{\sqrt{x^3+x^2}}{x}$, then $\displaystyle \frac{\sqrt{x^3+x^2}}{x}=\frac{\sqrt{x^2(x+1)}}{x} =\frac{x\sqrt{x+1}}{x}=\sqrt{x+1}$
how does $\displaystyle \frac{\sqrt{x^2(x+1)}}{x} $ equal $\displaystyle \frac{x \sqrt {x+1}}{x} $ ?
Originally Posted by hana_102 how does $\displaystyle \frac{\sqrt{x^2(x+1)}}{x} $ equal $\displaystyle \frac{x \sqrt {x+1}}{x} $ ? Think of it like this $\displaystyle [(x^2)(x+1)]^{\frac{1}{2}}$ Distribute the power of $\displaystyle \frac{1}{2}$ $\displaystyle x\sqrt{x+1}$
what if it was "For x0"?
Originally Posted by gearshifter what if it was "For x0"? If x=0 or x=-1, the radicand is 0. If x<-1, the radicand is negative thus producing imaginary solutions.
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