(4.0)(8.0)^z = (7.0)(3.0)^(z-1) I have to solve for z. I'm reviewing basic logarithm rules but I can't remember how to do this at all. Can someone provide some insight? Thanks!
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Hello, Originally Posted by Jeavus (4.0)(8.0)^z = (7.0)(3.0)^(z-1) I have to solve for z. I'm reviewing basic logarithm rules but I can't remember how to do this at all. Can someone provide some insight? Thanks! Just use the following rules :
Do I have to take the log of just the (8.0)^z and the (3.0)^(z-1)? Or the entire term itself? That's where I'm having trouble...
Originally Posted by Jeavus Do I have to take the log of just the (8.0)^z and the (3.0)^(z-1)? Or the entire term itself? That's where I'm having trouble... (a and b positive) So
Thanks! I got it!
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