Thread: How do I solve for this exponent using logs?

(4.0)(8.0)^z = (7.0)(3.0)^(z-1)

I have to solve for z. I'm reviewing basic logarithm rules but I can't remember how to do this at all.

Can someone provide some insight? Thanks!

Hello,

Originally Posted by Jeavus

(4.0)(8.0)^z = (7.0)(3.0)^(z-1)

I have to solve for z. I'm reviewing basic logarithm rules but I can't remember how to do this at all.

Can someone provide some insight? Thanks!

Just use the following rules :

Do I have to take the log of just the (8.0)^z and the (3.0)^(z-1)? Or the entire term itself? That's where I'm having trouble...

Originally Posted by Jeavus

Do I have to take the log of just the (8.0)^z and the (3.0)^(z-1)? Or the entire term itself? That's where I'm having trouble...

(a and b positive)

So

Thanks! I got it!