Can someone help me with this problem? I do not know how to work it... x = 9 (the square root of x)
Follow Math Help Forum on Facebook and Google+
x = 9*sqrt(x) => x^2 = 81x which gives x^2 - 81x = 0 or x(x - 81) = 0 x= 0, 81
The square root of x = 9 If that's what you're asking for then it's simply 9^2 which is 81. So the square root of 81 = 9. If that's not what you're asking for, then sorry I dont full understand what you're asking.
Originally Posted by damadama x = 9*sqrt(x) => x^2 = 81x which gives x^2 - 81x = 0 or x(x - 81) = 0 x= 0, 81 Ahh... this is it. Thanks for the explanation.
Originally Posted by TMU The square root of x = 9 If that's what you're asking for then it's simply 9^2 which is 81. So the square root of 81 = 9. If that's not what you're asking for, then sorry I dont full understand what you're asking. The reason you missed the x = 0 solution is that you divided both sides by which is an invalid procedure when x = 0. Tip: When you are dividing both sides of an equation always remember to set that factor equal to 0 to see if there might be another solution in there. -Dan
View Tag Cloud