This was a trial post to see if the equations would come up like they do for everyone else... but "No" it doesnt work out.

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- Sep 16th 2008, 09:55 PMJenny PhamSimplify exponential
This was a trial post to see if the equations would come up like they do for everyone else... but "No" it doesnt work out.

- Sep 16th 2008, 10:06 PMChris L T521
- Sep 16th 2008, 10:11 PMJenny Pham
I'm trying to post a to the power of 5, square root a to the power of 5, then divide all that by 2a to the power of 0.3

- Sep 16th 2008, 10:18 PM11rdc11
- Sep 16th 2008, 10:23 PMJenny Pham
Almost right. Lets see if i got this right (doubtful).

$\displaystyle

$$\displaystyle \frac{a^5 \sqrt a^5}{2a^{.3}}

$ - Sep 16th 2008, 10:25 PMChris L T521
- Sep 16th 2008, 10:27 PM11rdc11
Here is some info on latex

http://www.mathhelpforum.com/math-he...-tutorial.html - Sep 16th 2008, 10:34 PMJenny Pham
Perfect Chris!

I have no idea where all that "colour" came from as i just copied 11rdc11's formula. You gents have been great help. I better do some homework on the Latex stuff before i go off and embarrass myself again.

I have to admit, this forum stuff is pretty cool. I'm a first time user and the help provided is sensation.... I shall be back! - Sep 16th 2008, 10:38 PMJenny Pham
$\displaystyle \frac{a^5 \sqrt{a}^5}{2a^{.3}}$

Ok... I get it. Now for the BIG question "Do I now wait for an answer?" - Sep 16th 2008, 11:02 PM11rdc11
You want it simplfied?

$\displaystyle \frac{a^5a^{\frac{5}{2}}}{2a^{\frac{3}{10}}}= \frac{a^{\frac{15}{2}}}{2a^{\frac{3}{10}}}= \frac{a^{\frac{36}{5}}}{2} = \frac{(a^7)(a^{\frac{1}{5}})}{2}$ - Sep 17th 2008, 02:10 AMhana_102
- Sep 17th 2008, 04:07 AMmr fantastic
- Sep 17th 2008, 02:56 PMJenny Pham
You are a gem! Thanking you kindly for your assistance and solution 112rdc11.

- Sep 17th 2008, 03:04 PM11rdc11
- Sep 17th 2008, 03:06 PM11rdc11