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Math Help - solve this algebraic equation.

  1. #1
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    solve this algebraic equation.

    The original problem has to do with the interest rate at which 2 choices have the same present value, but I figured out the equation on my own. For some reason, I can't figure out how to solve it, even though I'm usually very comfortable with solving algebraic equations...

    6000 + (5940)/(1+i) =12000/[(1+i)^(1/2)]

    The answer is i = .21 (answer in the back of the book, works when plugged in) but I can't figure out how to get it.
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  2. #2
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    i was tryinhg to do this homework and i could not do it and it took me so much time.

    If f(x) = sin x and f(a) = 2/6, then what is the value of f(a) + f(pi + a) + f(2pi + a)?
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  3. #3
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by galalio View Post
    If f(x) = sin x and f(a) = 2/6, then what is the value of f(a) + f(pi + a) + f(2pi + a)?
    Don't post your question in someone else's thread. Make your own and post your question there.
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  4. #4
    Super Member 11rdc11's Avatar
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    \frac{6000(1 + i) +5940}{1+i} = \frac{12000}{\sqrt{1+i}}


    6000(1 + i) +5940 = 12000\sqrt{1+i}


    6000(1 + i) -12000\sqrt{1+i} +5940 = 0

    let u = \sqrt{1+i}

    so

    6000u^2 - 12000u + 5940 = 0

    Use quad formula and then remember to sub back in.
    Last edited by 11rdc11; September 16th 2008 at 09:19 PM.
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